98 is divisible by two, 99 is not, so 98.
99. Its 99. Wow Did you mean to say the largest odd two digit number?
It is 99.
84
50 - 25 = 25
No. When adding the smallest 2 digit number (= 10) to the smallest 2 digit number (again, 10) the result is a 2 digit number (10 + 10 = 20). When adding the largest 2 digit number (= 99) to the largest 2 digit number (again, 99) the result is a 3 digit number (99 + 99 = 198). As you can see, you'll either get a 2 or 3 digit number, but never a 4 digit number.
The largest two-digit even number is 98. In the decimal system, each digit can range from 0 to 9, but for a two-digit number, the first digit cannot be zero. Since we are looking for an even number, the last digit must be an even number, which leaves us with 0, 2, 4, 6, or 8. Among these options, 8 is the largest even digit, resulting in 98 as the largest two-digit even number.
The largest 5-digit even number is 99998. This number is even because it ends in an 8, which is an even digit. It is also the highest possible 5-digit number, just two less than 99999, the largest 5-digit number overall.
The largest two-digit number that is a multiple of 9 is 90. However, since it must also be even, the largest even two-digit multiple of 9 is 72. Therefore, the largest two-digit number that meets both criteria is 72.
How about 89
9797 is the largest two digit prime number.
199
679 is the product of the largest single-digit prime number and the largest two-digit prime number.
98 is the largest two digit number divisible by 7.
9 and 99
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.
For this type of "the largest number which..." questions, you need to advance from left to right, using the largest possible digit in each case. For the first two digits, that would be 9, for the third digit (the right-most digit), the largest digit which will make this possible is an 8.
99 + 9 = 108