98 is divisible by two, 99 is not, so 98.
90
99. Its 99. Wow Did you mean to say the largest odd two digit number?
It is 99.
84
No. There's no two digit numbers that could do this. The largest two digit number is 99. If you add 99 to itself, you only get 198, which is much smaller than a four digit number.
No. When adding the smallest 2 digit number (= 10) to the smallest 2 digit number (again, 10) the result is a 2 digit number (10 + 10 = 20). When adding the largest 2 digit number (= 99) to the largest 2 digit number (again, 99) the result is a 3 digit number (99 + 99 = 198). As you can see, you'll either get a 2 or 3 digit number, but never a 4 digit number.
How about 89
9797 is the largest two digit prime number.
199
679 is the product of the largest single-digit prime number and the largest two-digit prime number.
9 and 99
98 is the largest two digit number divisible by 7.
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.
For this type of "the largest number which..." questions, you need to advance from left to right, using the largest possible digit in each case. For the first two digits, that would be 9, for the third digit (the right-most digit), the largest digit which will make this possible is an 8.
99 + 9 = 108
The largest two-digit prime number is 97.
97=largest 2 digit prime
99. Its 99. Wow Did you mean to say the largest odd two digit number?