Ah, two acres is a lovely size to work with. Just imagine a square plot of land where each side is about 209 feet long. That's the length and width of two acres, a perfect space to let your creativity and imagination run wild. Just think of all the happy little trees and bushes you could plant there!
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There are an infinite number of answers.
Given that the length is greater than the width, and that the total area is 2 acres = 87120 sq ft, then the length can be any vaue greater than or equal to sqrt(87120) feet ie approx 295.2 feet.
For any such length, L, the width would be 87120/L feet.
A 2 acre plot could be
8712 ft * 10 ft
87120 ft * 1 ft
or even 87120000 ft * 0.001 ft
From the Wikipedia article: an acre was originally surveyed as 66 feet X 660 feet. Most likely, the shorter dimension was doubled to get 2 acres, which would make it 132 feet x 660 feet.
It is 2*(Length + Width).
It is length•2+width•2 So if you have the length u can find the width
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm