There is an infinite number of cube numbers and there is not enough time in the life of the solar system to answer the question.
8 and 27 are the only two perfect cubes in the range.
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
A number cube, also known as a six-sided die, has numbers 1 through 6 on its faces. Therefore, there are six numbers on a number cube.
The answer is 216. The list contains the cubes (raised to the third power) of the numbers 1 through 5. The cube of the next number, 6, is 216.
Let's denote the two cube numbers as (a^3) and (b^3), where (a) and (b) are integers. We are looking for two cube numbers that satisfy the equation (a^3 + b^3 = 28). By testing different values, we find that (1^3 + 3^3 = 1 + 27 = 28), so the cube numbers 1 and 3 add up to make 28.
There are infinitely many of them and so it is not possible to list them.
8 and 27 are the only two perfect cubes in the range.
1 (1x1x1),8 (2x2x2),27 (3x3x3),64 (4x4x4).
list of few things that look like a cube?
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
No
Yes.
A number cube, also known as a six-sided die, has numbers 1 through 6 on its faces. Therefore, there are six numbers on a number cube.
The answer is 216. The list contains the cubes (raised to the third power) of the numbers 1 through 5. The cube of the next number, 6, is 216.
Let's denote the two cube numbers as (a^3) and (b^3), where (a) and (b) are integers. We are looking for two cube numbers that satisfy the equation (a^3 + b^3 = 28). By testing different values, we find that (1^3 + 3^3 = 1 + 27 = 28), so the cube numbers 1 and 3 add up to make 28.
Sixth powers.
Any "cube" has 6 faces, so you could have 6 different numbers, as on dice.