There is an infinite number of cube numbers and there is not enough time in the life of the solar system to answer the question.
8 and 27 are the only two perfect cubes in the range.
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
A number cube, also known as a six-sided die, has numbers 1 through 6 on its faces. Therefore, there are six numbers on a number cube.
The answer is 216. The list contains the cubes (raised to the third power) of the numbers 1 through 5. The cube of the next number, 6, is 216.
Let's denote the two cube numbers as (a^3) and (b^3), where (a) and (b) are integers. We are looking for two cube numbers that satisfy the equation (a^3 + b^3 = 28). By testing different values, we find that (1^3 + 3^3 = 1 + 27 = 28), so the cube numbers 1 and 3 add up to make 28.
There are infinitely many of them and so it is not possible to list them.
8 and 27 are the only two perfect cubes in the range.
1 (1x1x1),8 (2x2x2),27 (3x3x3),64 (4x4x4).
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
list of few things that look like a cube?
No
Yes.
A number cube, also known as a six-sided die, has numbers 1 through 6 on its faces. Therefore, there are six numbers on a number cube.
To find how many cube numbers are between 2000 and 4000, we first calculate the cube roots of these numbers. The cube root of 2000 is approximately 12.6, and the cube root of 4000 is approximately 15.9. The integer cube numbers within this range correspond to 13, 14, and 15, which are (13^3 = 2197), (14^3 = 2744), and (15^3 = 3375). Therefore, there are three cube numbers between 2000 and 4000.
Sixth powers.
The answer is 216. The list contains the cubes (raised to the third power) of the numbers 1 through 5. The cube of the next number, 6, is 216.
Let's denote the two cube numbers as (a^3) and (b^3), where (a) and (b) are integers. We are looking for two cube numbers that satisfy the equation (a^3 + b^3 = 28). By testing different values, we find that (1^3 + 3^3 = 1 + 27 = 28), so the cube numbers 1 and 3 add up to make 28.