The biggest number that can be formed with just those four digits once each, is 8641 - however - no number made from those digits can be divided by 9 because in order for a number to be exactly divisible by nine - the sum of the digits must also divide exactly by nine. The sum of the digits 6, 4 8 & 1 is 19 !
Another Answer:-
The above answer is absolutely correct.
A possible solution is 61+8/4 = 63 and 7*9 = 63
There are 2000 such numbers.
A number is divisible by 3 if the sum of its digits is divisible by 3.
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
If the last 3 digits are divisible by 8 and the sum of the digits are divisible by 9.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
5 ^12
33 = 27 with repetition, 3! = 3*2*1 = 6 without repetition.
There are 2000 such numbers.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
15 of them.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
9876543210
30 without repetition (6P2) 66 with repetition (12C2)
There are 2000 such numbers.
To be irrational, it would have to have an infinite number of digits, without a periodic repetition.
A number is divisible by 3 if the sum of its digits is divisible by 3.