You use the dot operator when the left side is the name of the object or a reference to an object, and you use the arrow operator when the left side is a pointer to an object. Example: struct foobar x, *p= &x; x.field = p->field; (&x)->field = (*p).field;
\sqrt(9.8)~ 3.13
Password dotmate
Rectangle right? If so, here is the formula. P= S + S + S + S P= 16 + 16 + 12 + 12 P= 16 + 16 +24 P= 16 + 40 P= 56 feet. You can shorten the steps, I just wanted to show all of the math.
Well.... there is pythagoras.
GB
.. P / | \ p-p-p .. .. ..
P..h.p
You use the dot operator when the left side is the name of the object or a reference to an object, and you use the arrow operator when the left side is a pointer to an object. Example: struct foobar x, *p= &x; x.field = p->field; (&x)->field = (*p).field;
"P" stands for point. As in Jacketed Hollow Point.
P= S + S + S + S P= # + # + # + # P= answer
P= F.v, where P is power, and F.v is the dot product of the Force and velocity vectors.
It wasnt me.... :P
Publix
paisley plaid polka-dot
Phosphorous is represented as P, and has 5 valence electrons. It is a nonmetal, so it will have brackets [].It is extremely difficult to recreate it without a picture, so here is an attempt. Please ignore the underscores._. .[.P.]_ .In words, put P in brackets []. [P]Add two dots on top.Add one dot on the other sides.There should now be five dots total, representing the number of valence electrons (outermost shell).
because u are dom lol :P