Probably an arc, but it is not possible to be certain because there is no information on where or what point b and c are..
The answer will depend on the location of the points B, P and C.
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It is a RayA ray is part of a line which is finite in one direction, but infinite in the other. It can be defined by two points, the initial point, A, and one other, B. The ray is all the points in the line segment between A and B together with all points, C, on the line through A and B such that the points appear on the line in the order A, B, C.Source: Faber, Richard L. (1983). Foundations of Euclidean and Non-Euclidean Geometry. New York, United States: Marcel Dekker. ISBN 0-8247-1748-1.
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An arc.
The measure of arc AB is 115 degrees. This indicates that the arc, which is a part of a circle defined by points A and B, subtends an angle of 115 degrees at the center of the circle. Therefore, if you were to measure the angle formed at the center by lines drawn to points A and B, it would be 115 degrees.
exactly three times as far from point A as they are from point B?
Three noncollinear points A, B, and C determine exactly three lines. Each pair of points can be connected to form a line: line AB between points A and B, line AC between points A and C, and line BC between points B and C. Thus, the total number of lines determined by points A, B, and C is three.
The analogy for d-B to r is like comparing the distance between two points on a straight line (d-B) to the radius of a circle (r). Just as the radius measures the distance from the center of a circle to any point on its circumference, d-B represents the shortest distance between two points on a line.
distance
The answer will depend on the location of the points B, P and C.
a circle 9 cm from point b I was co fused by this but you just do a diagram and write this
It takes 3 non collinear points to define one specific circle. With only two points an infinite number of circles can be drawn. Proof: Given two points A, B draw the line between them. Then find the perpendicular bisector of the line AB. Any point on the perpendicular bisector is equidistant from the two original points, A and B. A circle with center C and radius AC will then pass through points A and B. There are infinite point C's on the perpendicular bisector so there are infinite circles. Given three points A, B and D you can find the perpendicular bisector for line segements AB and then the perpendicular bisector fof line segment BC. The two perpedicular bisectors will not be parallel because the points A, B and D are non collinear. This means the two perpeniducar bisectors will intercept at only one point C(like any two intercepting lines). This point C is equidistant from points A, B, and D. A circle with center C and radius AC will then pass through all three of the points. Since there is only one point C that lies on both perpendicular bisectors, there is only one circle possible.
This starts with the collocation circle to go through the three points on the curve. First write the equation of a circle. Then write three equations that force the collocation circle to go through the three points on the curve. Last, solve the equations for a, b, and r.
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