Three noncollinear points A, B, and C determine exactly three lines. Each pair of points can be connected to form a line: line AB between points A and B, line AC between points A and C, and line BC between points B and C. Thus, the total number of lines determined by points A, B, and C is three.
Three noncollinear points ( A ), ( B ), and ( C ) determine exactly three lines: line ( AB ), line ( BC ), and line ( AC ). Each pair of points defines a unique line, and since the points are noncollinear, no two lines coincide. Thus, the total number of lines determined by points ( A ), ( B ), and ( C ) is three.
If you are talking about straight lines, the answer is NONE, because that is what noncollinear means. If curves are allowed, then the answer is infinitely many.
there are 6 lines can pass through 4 noncollinear points.
Three lines are determined by three points unless the points are all on the same line ( i.e. co-linear)
One.exactly one
Three noncollinear points ( A ), ( B ), and ( C ) determine exactly three lines: line ( AB ), line ( BC ), and line ( AC ). Each pair of points defines a unique line, and since the points are noncollinear, no two lines coincide. Thus, the total number of lines determined by points ( A ), ( B ), and ( C ) is three.
If you are talking about straight lines, the answer is NONE, because that is what noncollinear means. If curves are allowed, then the answer is infinitely many.
there are 6 lines can pass through 4 noncollinear points.
1 line cause every plane contains atleast 3 or more noncollinear points
exactly one and only one.
3 non-collinear points define one plane.
Any Euclidean plane has infinitely many points.
3
3 or more
Three.
Three lines are determined by three points unless the points are all on the same line ( i.e. co-linear)
One.exactly one