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The third number is 2 -- the first number is 1, second is 1, next is 1+1=2, then 1+2=3, 2+5=5 etc.
There are infinitely many pairs. 1) Pick a value for one of the numbers - call this A 2) The second number, B = 0.47 - A
from 1-9 have 9 numbers so that we have 9*9*9*9*9=59049 Consider the case of 5-digit number combinations, where each is some digit from 1 through 9. There are 9 different digits you can pick for the first number. Assuming you can have repeats, there are 9 you can pick for the second, 9 you can pick for the third, and 9 you can pick for the fourth and 9 you can pick for the fifth.
1 is odd and 2 is even? 1 is actually a prime number, 2 is considered an even number. But it is also a prime number
1-(2)3-(5)8-(11)19-(23)42-(?)? 0*2=1 = 1 1*2=2 + 1 = 3 2*2+1 = 5 + preceding number = 8 5*2+1 = 11 + preceding number = 19 11*2+1 = 23 + preceding number = 42 23*2+1 = 47 + preceding number = 89 so I think the answer is 89.