120 = 2 x 2 x 2 x 3 x 5
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The prime factorization of 122 is: 2 × 61 The prime factorization of 35 is: 5 × 7 The prime factorization of 120 is: 2 × 2 × 2 × 3 × 5 The prime factorization of 15 is: 3 × 5
The Highest Common Factor (HCF) of 120 and 65 is the largest positive integer that divides both 120 and 65 without leaving a remainder. To find the HCF, you can use the Euclidean algorithm or prime factorization method. In this case, the prime factorization of 120 is 2^3 * 3 * 5 and the prime factorization of 65 is 5 * 13. The common factors are 5, so the HCF of 120 and 65 is 5.
As a product of its prime factors using exponents: 2^3 times 3 times 5 = 120
The GCF of 88, 96, 120 is 8. The prime factorization of 88 is 2*2*2*11 The prime factorization of 96 is 2*2*2*2*2*3 The prime factorization of 120 is 2*2*2*3*5 The GCF is 2*2*2 = 8.
The Highest Common Factor (HCF) of 120 and 180 is the largest number that divides both 120 and 180 without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factorization of 120 is 2^3 * 3 * 5, and the prime factorization of 180 is 2^2 * 3^2 * 5. To find the HCF, we take the product of the common prime factors with the lowest exponent, which is 2^2 * 3 = 12. Therefore, the HCF of 120 and 180 is 12.