This quadratic equation has no real roots because its discriminant is less than zero.
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
It is a mathematical equation, usually written like this: 5x - 7 + 2x = 3x - 2 + 4x
5x + 4 = 6x - 2Add 2 to each side of the equation:5x + 6 = 6xSubtract 5x from each side:6 = x
5 and the y intercept is 2
This quadratic equation has no real roots because its discriminant is less than zero.
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
Multiply the bottom equation by -1
yes it is!
-7 therefore the quadratic equation has no real roots
5x2 + 12x + 7 = 0 This equation can be factored : (5x + 7) (x + 1) = 0 The equation equals zero when either 5x + 7 = 0 or x + 1 = 0 When 5x + 7 = 0 then 5x = -7 : x = -7/5 or -1.4 When x + 1 = 0 then x = -1 The solutions or roots of this equation are x = -7/5 and x = -1
7x + 8 = 5x + 327x = 5x + 242x = 24x = 12hope this helps
It is an equation and the value of x is 2
There is no one answer. This is an equation for a straight line.
y=-5x+8 the slope is -5.
In the equation 43X +2=5X, X=-1/19.
It is a quadratic equation in the variable x.