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She will be 24.

S=16 (Sarah is 16 years old)

S=4B (Sarah is 4 times as old as her brother)

S/4=B

16/4=B

B=4 (Sarah's brother is 4 years old)

How old will Sarah be when she is twice as old as her brother?

S+Y=2(B+Y); S= Sarah's age, B= Sarah's Brother's age, Y=years passed

16+Y=2(4+Y)

16+Y=8+2Y

16=8+2Y-Y

16=8+Y

16-8=Y

8=Y (Sarah will be twice as old as her brother after 8 years pass)

How old is Sarah after 8 years pass?

S+Y=Final Answer

16+8=24

Checking work:

B+Y=4+8=12

Is 12 half of 24? Yes.

Therefore Sarah will be twice her brothers age when she is 24 and her brother will be 12.

-------------------

The keys here are

Sarah's age S = 16

Sarah's brother's age B = 16/4 = 4

Years that pass = T

The equation is

Sarah's future age is twice her brother's future age

16+T = 2 (4+T)

16+T = 8 +2T

16 = 8+2T - T

16 = 8 + T

8 = T

Sarah's future age = 16 + T = 24

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Q: Sarah is sixteen years old and four times as old as her brother How old will Sarah be when she is twice as old as her brother?
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