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Given any number it is easy to find a rule based on a polynomial of order 7 such that the first seven numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.

The simplest polynomial solution, of order 6, is

T(n) = (n^6 - 21*n^5 + 175*n^4 - 723*n^3 + 1612*n^2 - 1668*n + 648)/24 for n = 1 , 2, 3, ...

Accordingly, the next term in the sequence is 463.

Q: Select the next number in the series 1 7 18 37 67 111 202?

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202

Oh, dude, let me grab my crystal ball real quick. Okay, so if we're talking about this series, the next number is 1999. How did I figure that out? Well, I just closed my eyes, made a wild guess, and hoped for the best. Like, who even needs math when you have intuition, am I right?

111.

The exponent of 111 is 0. 1110 = 111 . Any number raised to the power of zero is that number.

It is 129.

Related questions

202

129 The numbers are prime (don't consider the prefix 1)

There are an infinite amount of numbers after 110 but the next whole number or integer is 111

Oh, dude, let me grab my crystal ball real quick. Okay, so if we're talking about this series, the next number is 1999. How did I figure that out? Well, I just closed my eyes, made a wild guess, and hoped for the best. Like, who even needs math when you have intuition, am I right?

They are Roman numerals for 109 and 110 so the next numerals are cxi which equals 111

111.

111 is an odd number.

The exponent of 111 is 0. 1110 = 111 . Any number raised to the power of zero is that number.

It is 129.

119

If a number has only two factors then it is prime. For every natural number(except 1) we are sure about its two factors: 1 and the number itself. So the two factors we already know of 111 are 1 and 111. So if there exists some number which divides 111 evenly then 111 has more than two factors implies 111 is a composite number. 111 is not a prime number because it is divisible by 3.

22,200 is a number that can be divisible by 111 and 200.