There are eight numbers: 3, 9, 15, 21, 27, 33, 39, 45.
1,2,3,4,5,6,7,8
8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.
The numbers that are divisible by both 3 and 5 have to be a factor of 15. That leaves 15, 30, 45, 60, 75, and 90. There are 6 numbers less than 100 divisible by 3 and 5
The natural numbers are the counting numbers Thus the set m of those counting numbers less than 5 is: m = {1, 2, 3, 4}
858
14 of them.
According to a source, there are 44 counting numbers less than 200 that are exactly divisible by either 6 or 9, or by both. To determine the total count, we can follow these steps: Find out how many counting numbers less than 200 are divisible by 6. The last number under 200 that is divisible by 6 is 198, and since 198 is the 33rd multiple of 6, there are 33 such numbers. Next, figure out how many numbers are divisible by 9. The last number under 200 that is divisible by 9 is also 198, and since 198 is the 22nd multiple of 9, there are 22 such numbers. Some numbers will be divisible by both 6 and 9, but we need to avoid counting these twice. So, determine which numbers are divisible by both (these are actually multiples of 18). The last number under 200 that is divisible by 18 is also 198, and since it is the 11th multiple of 18, there are 11 such numbers. Finally, add the two individual counts from steps 1 and 2 together and subtract the count from step 3 to eliminate double counting: 33 + 22 - 11 = 44. Therefore, there are 44 different counting numbers less than 200 that are exactly divisible by either 6 or 9 or both.
There are eight numbers: 3, 9, 15, 21, 27, 33, 39, 45.
alm ko po ay {2,4,6,8,1,0,12,1,4,16,18,20,.......}\ :)
14. Assuming dealing with only counting numbers (ie integers greater than 0): Numbers divisible by 5 or 7 are their multiples. 50 ÷ 5 = 10 → last multiple of 5 less than 50 is 9 x 5 → 9 numbers less than 50 are divisible by 5 50 ÷ 7 = 71/7 → last multiple of 7 less than 50 is 7 x 7 → 7 numbers less than 50 are divisible by 7 Numbers divisible by both are those which are multiples of their lowest common multiple = 35 50 ÷ 35 = 115/35 → last multiple of 35 less than 50 is 1 x 35 → 1 number less than 50 is divisible by both 5 and 7 and needs to be removed from both the above counts. → (9 - 1) + (7 - 1) = 14 numbers less than 50 are divisible by 5 or 7 but not both. If there is no restriction on numbers being greater than 0, there are infinitely many numbers as it includes the infinite number of negative numbers which are all less than 50 and provide an infinite number of numbers divisible by 5 or 7 but not both.
How many numbers less than 700 are divisible by both 15 and 21?
1,2,3,4,5,6,7,8
The natural numbers are the counting numbers. Therefore, the natural numbers less than 31 are the numbers from 1 to 30.
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96,100 ............ on and on and on to infinity and beyond LOL !!!!!!!!!
50
8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.