Suppose x is a rational number and y is an irrational number.
Let x + y = z, and assume that z is a rational number.
The set of rational number is a group.
This implies that since x is rational, -x is rational [invertibility].
Then, since z and -x are rational, z - x must be rational [closure].
But z - x = y which implies that y is rational.
That contradicts the fact that y is an irrational number. The contradiction implies that the assumption [that z is rational] is incorrect.
Thus, the sum of a rational number x and an irrational number y cannot be rational.
Suppose x is a rational number and y is an irrational number.
Let x + y = z, and assume that z is a rational number.
The set of rational number is a group.
This implies that since x is rational, -x is rational [invertibility].
Then, since z and -x are rational, z - x must be rational [closure].
But z - x = y which implies that y is rational.
That contradicts the fact that y is an irrational number. The contradiction implies that the assumption [that z is rational] is incorrect.
Thus, the sum of a rational number x and an irrational number y cannot be rational.
No. In fact, the sum of conjugate irrational numbers is always rational.For example, 2 + sqrt(3) and 2 - sqrt(3) are both irrational, but their sum is 4, which is rational.
Let R1 = rational number Let X = irrational number Assume R1 + X = (some rational number) We add -R1 to both sides, and we get: -R1 + x = (some irrational number) + (-R1), thus X = (SIR) + (-R1), which implies that X, an irrational number, is the sum of two rational numbers, which is a contradiction. Thus, the sum of a rational number and an irrational number is always irrational. (Proof by contradiction)
Yes
That simply isn't true. The sum of two irrational numbers CAN BE rational, but it can also be irrational. As an example, the square root of 2 plus the square root of 2 is irrational.
an irrational number PROOF : Let x be any rational number and y be any irrational number. let us assume that their sum is rational which is ( z ) x + y = z if x is a rational number then ( -x ) will also be a rational number. Therefore, x + y + (-x) = a rational number this implies that y is also rational BUT HERE IS THE CONTRADICTION as we assumed y an irrational number. Hence, our assumption is wrong. This states that x + y is not rational. HENCE PROVEDit will always be irrational.
It is always irrational.
Such a sum is always rational.
Such a sum is always irrational.
Since the sum of two rational numbers is rational, the answer will be the same as for the sum of an irrational and a single rational number. It is always irrational.
Yes.
They are always rational.
Yes, always.
Yes, that is so.
It is always an irrational number.
It is always an irrational number.
Wrong. It is always an irrational number.
No. In fact, the sum of conjugate irrational numbers is always rational.For example, 2 + sqrt(3) and 2 - sqrt(3) are both irrational, but their sum is 4, which is rational.