To simplify the expression (X^2 - 1) / (X - 1), we can first factor the numerator as a difference of squares: (X^2 - 1) = (X + 1)(X - 1). Then, we can rewrite the expression as ((X + 1)(X - 1)) / (X - 1). Next, we can cancel out the common factor of (X - 1) in the numerator and denominator, leaving us with the simplified expression of X + 1.
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
start by differentiating each component d/dx [x2]=2x d/dx [lnx]=1/x product rule 2xlnx+x2/x simplify (factoring) x[2ln(x)+1]
x2/(-x) = -x.
x2+x-6=x2+3x-2x-6x2+x-6=x(x+3)-2(x-3)x2+x-6=(x+3)(x-2)
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
1/x2
The antiderivative of x/(x2-1) is ln(x2-1)/2. Proof: (ln(x2-1)/2)' = (1/(x2-1))*(x2-1)'/2=1/(x2-1)*(2x/2)=x/(x2-1).
Assuming simplify = factor...x3 - 3x + 2 = (x-1)(x2+x-2)
x ÷ 2x2 = 1/2x
x(x + 2)
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results:
The law of powers requires that xn divided by xm = x(n - m). Consider this when n = m: xn divided by xn = x(n - n), ie 1 = x0. x2 = x times x x1 = x times x divided by x ie x x0 = x divided by x = 1 x-1 = 1 divided by x = 1/x x-2 = 1/x divided by x ie 1/x2 etc
By factorisation: x2 + 6xy - 27y2 = (x + 9y)(x - 3y).
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
start by differentiating each component d/dx [x2]=2x d/dx [lnx]=1/x product rule 2xlnx+x2/x simplify (factoring) x[2ln(x)+1]