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(X^2 - 1)/(x-1) = (X+1)(X-1)/(X-1) = X+1
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How do you Factor x cubed plus one divided by x plus one?
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
How do you find derivative of x2lnx?
start by differentiating each component d/dx [x2]=2x d/dx [lnx]=1/x product rule 2xlnx+x2/x simplify (factoring) x[2ln(x)+1]
What is x squared divided by -x?
x2/(-x) = -x.
How do you simplify x squared plus x-6?
x2+x-6=x2+3x-2x-6x2+x-6=x(x+3)-2(x-3)x2+x-6=(x+3)(x-2)
What is x plus 4 divided by x3 -11x plus 20?
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
How do you simplify the equation x2 plus 4x-5 divided by x plus 5 I am stuck?
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
What is x divided by x cubed?
1/x2
What is the anti derivative of x divided by x squared minus 1?
The antiderivative of x/(x2-1) is ln(x2-1)/2. Proof: (ln(x2-1)/2)' = (1/(x2-1))*(x2-1)'/2=1/(x2-1)*(2x/2)=x/(x2-1).
How to simplify x cube - 3x plus 2?
Assuming simplify = factor...x3 - 3x + 2 = (x-1)(x2+x-2)
What is x divided by 2 x2?
x ÷ 2x2 = 1/2x
Simplify x2 plus 2x?
x(x + 2)
How do you Factor x cubed plus one divided by x plus one?
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
How any number o the power of zero is one?
The law of powers requires that xn divided by xm = x(n - m). Consider this when n = m: xn divided by xn = x(n - n), ie 1 = x0. x2 = x times x x1 = x times x divided by x ie x x0 = x divided by x = 1 x-1 = 1 divided by x = 1/x x-2 = 1/x divided by x ie 1/x2 etc
Given 3x3 plus 4x2 plus x plus 7 is divided by x2 plus 1?
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results:
How do you simplify x2 plus 6xy - 27y2?
By factorisation: x2 + 6xy - 27y2 = (x + 9y)(x - 3y).
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
How do you find derivative of x2lnx?
start by differentiating each component d/dx [x2]=2x d/dx [lnx]=1/x product rule 2xlnx+x2/x simplify (factoring) x[2ln(x)+1]
