98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
9.899494936611665It is: 7 times square root of 2± 9.899495
Expressed as a surd, sqrt(98) + sqrt(2) = 8 sqrt(2).
The square root of 9604 = 98. (98 x 98 = 9604)
The square root of 49 is 7, because 7 x 7 = 49
98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
It is 7 times the square root of 2
sq. root of 98 =sq. root of 49*2 =7*sq.root of 2 =7*1.414 =9.898
7square roots of 2
No because the square root of 98 is 7 times the square root of 2
The simplified square root of 98 is: ±9.9 or ±10
No. If the square root of 98 was an integer, 98 would be a perfect square.
The square root of 9604 is 98.
√98 ~= 9.899
49
49
It is 98 because 98*98 = 9604