7 x 2½
sqrt(98) = sqrt( 2 x 49(_ = sqrt(2) X sqrt(49) = sqrt(2) X 7 usually written as 7sqrt(2) (Surd form) Numerically the answer is 9,899494937.....
9.899494936611665It is: 7 times square root of 2± 9.899495
Expressed as a surd, sqrt(98) + sqrt(2) = 8 sqrt(2).
The square root of 9604 = 98. (98 x 98 = 9604)
The square root of 49 is 7, because 7 x 7 = 49
To simplify radical 98, first, factor it into its prime factors: (98 = 49 \times 2), where 49 is a perfect square. The square root of 49 is 7, so you can rewrite (\sqrt{98}) as (\sqrt{49 \times 2} = \sqrt{49} \times \sqrt{2} = 7\sqrt{2}). Therefore, the simplified form of (\sqrt{98}) is (7\sqrt{2}).
It is 7 times the square root of 2
sq. root of 98 =sq. root of 49*2 =7*sq.root of 2 =7*1.414 =9.898
7square roots of 2
sqrt(98) = sqrt( 2 x 49(_ = sqrt(2) X sqrt(49) = sqrt(2) X 7 usually written as 7sqrt(2) (Surd form) Numerically the answer is 9,899494937.....
No because the square root of 98 is 7 times the square root of 2
The simplified square root of 98 is: ±9.9 or ±10
No. If the square root of 98 was an integer, 98 would be a perfect square.
The square root of 9604 is 98.
√98 ~= 9.899
49
49