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4r +3 = 3r-2

r + 3=-2

r=-5

basically

collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.

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Q: Solve 4r plus 3 equals 3r- 2 for r?
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