The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation:
y = -4x - 7;
3x = = -4x - 7;
7x = -7;
x = -1.
Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus:
y = 3x;
y = 3(-1)
y = -3.
Thus, the solution to this system of equations is (-1, -3).
y= -4x-7 y=3x 3x= -4x-7 3x+4x=7 7x=7 x=1
this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7
3x+y = 10 y = x-2 Substitute the value of y into the top equation: 3x+x-2 = 10 => 4x = 10+2 => 4x = 12 => x = 3 Substitute the value of x into the original equations to find the value of y: So: x = 3 and y = 1
4x=3x+1 => (4x-3x)=1 => x=1 therefore the value of x is 1.
3x + 4x = 847x = 84divide both sides by 7x = 12
y= -4x-7 y=3x 3x= -4x-7 3x+4x=7 7x=7 x=1
4x-y=2, thereforey=4x-2sub y into 3x+2y=6...3x+8x-4=611x=10x=10/11
4x+7-3x = 15 4x-3x = 15-7 x = 8
3x = 7 - 4x 3x + 4x = 7 - 4x + 4x 7x = 7 7x/7 = 7/7 x = 1
3x+7=4x-73x=(-)7+4x-4x(-)1x=(-)7________(-)1x=7add (-3x) to each side of equation3x +7 = 4x-3x +3x +7 = 4x -3x0 +7= 1x7=x
7x = 3x - 12 4x=-12 x=-3
5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5
From second equation: y = 8 + 2xSubstitute for y in first equation: 3x + 16 + 4x = 2ie 7x = -14ie x = -2 and y = 4
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
x + 5 = 4x/3 Solve for x multiply both sides of the equation by 3... 3 * (x + 5) = 3 * (4x/3) 3x + 15 = 4x subtract 3x from both sides of the equation (3x + 15) - 3x = (4x) - 3x 15 = x x = 15
5+4x-7=4x+3-1x 4x-2=3x+3 (combined the like terms) +2 +2 (add 2 to both sides) 4x=3x+5 -3x -3x (subtract 3x from both sides) x+5
You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?