3x=(33+42) 3x=75 x=75/3 x=25
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
Algebraically. X + (X + 1) + (X + 2) = 288 3X + 3 = 288 3X = 285 X = 95 X + 1 = 96 X + 2 = 97 95 + 96 + 97 = 288 ---------------------------------so (95, 96, 97 ) -----------------the three consecutive numbers
x . 9 =12-3x9x =12-3x9x+3x=1212x =12x =1
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
3x = (96-75) 3x = 21So X = 7
3x=96-75 3x=21 x=7
Solve for x: 3x=(96-75) 96-75= 21 / 21:3= 7
x=7
7
First you simplify: 3x=21 Then you divide both sides by 3: x=7
3x = 96 - 75 produces the equations 3x = 21 and x = 7
In 3x = 96 - 75 the "x" stands for the number which, when multiplied by 3, equals the difference between 96 and 75. 96 - 75 = 21 If 3x = 21 then x = 21 divided by 3, or 7
X + x + 1 + x + 2 = 96 3x + 3 = 96 3x = 93 x = 31 31,32,33
3x=(33+42) 3x=75 x=75/3 x=25
171
3x=24 x=8