Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
33/3 = 11 so the three are 9, 11 and 13
Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.-3, -1, 1 and 3.
-1, -3 and -8
31, 32, 33
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
96
96
Average is 96/3 ie 32 so integers are 30, 32 and 34.
96
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
They are are 62, 63 and 64.
To figure this out, divide 96 by three, ignoring the remainder for now. This gives the number 30. The remainder is 6. Three consecutive numbers that add up to six are 1, 2 and 3. So the three consecutive integers are 31, 32, and 33.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.