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you can not solve this equation
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
The equation 7 x + 14 y + 10 z = 98001 has infinite solutions. For any x and y we can have a z which satisfies this equation. For example, if we choose x=1 and y=1 then z=9798 satisfies. To have a specific solution there must be three equations for three unknowns (x,y,z), which can be solved simultaneously.
To find what z-score represents the 80th percentile, simply solve for 0.8 = F(z), where F(x) is the standard normal cumulative distribution function. Solving gives us: z = 0.842
If x = y and y = z then x = z
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
To solve for x when z equals y divided by x, you can rearrange the equation to isolate x. Start by multiplying both sides by x to get xz = y. Then, divide both sides by z to solve for x, giving you x = y/z. This is the solution for x when z equals y divided by x.
(1/x) - (1/y) = (1/z) Get the left-hand side over a common denominator:- (y-x)/xy = 1/z Take the reciprocal of both sides:- z = xy / (y-x)
you can not solve this equation
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
y=84-72=12 z=84-52=32 x=84-12-32=40
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q
The idea here is to transfer to the other side everything you don't need. x = yz yz = x (switching both sides) y = x/z (you divide both sides by z, since you want to get rid of the z on the left side).
k = 2 Explanation: when z varies directly proportional to x means a division c = z x where c is a constant of proportionality when z varies inversely proportional to x it means a product z y = c now with both k = z y x z = 8 ; x = 12 and y = 3 k = 8.3 12 k = 2
I tried to find f by integrating the partial derivatives, but since 1/r is multiplying the whole vector, I just took it out, I'm not sure if I can do that. Like this: ∂f∂x(x,y,z)=x ∂f∂y(x,y,z)=y ∂f∂z(x,y,z)=z thus f(x,y,z)=x22+g(y,z) f(x,y,z)=y22+h(x,z) f(x,y,z)=z22+k(x,y) for some functions g, h, and k, so if g=y22+z22, h=x22+z22 and k=x22+y22, the function f is: f(x,y,z)=1r(x22+y22+z22)=12r⋅r2=r2 Am I correct? If not, how can I solve this correctly, should I integrate x/r, y/r and z/r instead?