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x^2+y^2=25 and y=x-7. This question is interesting since the first equation is a circle of radius 5 and the second is a line with slope 1 and y intercept -7. The solution will be the where the line intersects the circle. If you plug in y=x-7 into the equation of the circle and solve for x you can find he answer. Plugging in x-7 for y we have 2x^2-14x+49=25 or 2x^2-14x+24=0 which we can factor as 2(x-3)(x-4) So the solutions are x=3 and x=4. If you plug that into the equation of the line you find y=4-7, so y=-3 and y=3-7 so y=-4. The solutions are (4,-3) and (3,-4). This means the line intersects the circle in two points.

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Q: Solve simultaneously x to the power of 2 plus y to the power of 2 equals 25 and y equals x-7?
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