y = 11
If you mean 8y-2y = 132 then 6y = 132 and the value of y is 22
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.
To divide 15840 by 132, you would perform long division. Start by dividing 15840 by 132, which equals 120. Then multiply 120 by 132, which equals 15840. This shows that 15840 divided by 132 equals 120.
12 x 11 = 132
12y = 132y = 132/12y = 11
y = 11
It is the same as: 11z = 132 Divide both sides by 11: z = 12
C. p ‹ 12
132
If you mean 8y-2y = 132 then 6y = 132 and the value of y is 22
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.
what equals 132 is 12*11=132
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
12 x 11 = 132
132
133 - 1 = 132