y = 11
If you mean 8y-2y = 132 then 6y = 132 and the value of y is 22
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.
12 x 11 = 132
11 times 12 = 132
12y = 132y = 132/12y = 11
y = 11
It is the same as: 11z = 132 Divide both sides by 11: z = 12
C. p ‹ 12
132
If you mean 8y-2y = 132 then 6y = 132 and the value of y is 22
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.
what equals 132 is 12*11=132
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
12 x 11 = 132
132
133 - 1 = 132