x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
81 x 81 = 6561
9/10 divided by 10/9 equals 9/10 x 9/10 equals 81 /100
It is: 9^2 = 81
x: x2 - 81 = 0
34 = 81 so x is 4
23
x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
It then equals 1/81
54
92y = 36 y = 36/92 = 9/23 Then: 9y = 81/23
1/3 = 27/81
-100/63 ÷ 10/81 = -90/7 or -126/7
log9(x)=2 x=9^2 x=81
84
81% = 81/100