solve x=yz for the variable y
Solve the standard form for the dependent variable, commonly 'y'.
It all depends on what xyz is. If xyz is an arc of a curve, there will be no vertex whereas if xyz is a triangle, each of x, y and z will be a vertex.
The basic idea here is to look at both equations and solve for either x or y in one of the equations. Then plug the known value into the second equation and solve for the other variable.
32
Instead of just giving you the answer, I'll tell you how to solve the problem. To solve this problem, write two equations. Let one variable be x and the other y. Then you can say: xy = 800 x + y = -70 Isolate x + y = -70 for y and you get y = -70-x Then plug it back into the first equation, solve for x and plug your answer into the second equation to solve for y. Hope that helps, and let me know if you have any questions :)
you make x=0 and solve for y. for the x intercept you do y=0 and solve for x
You use variable in math problems to help you solve the answer. For example, you could do 50+50=a. The (a) would be the variable. Or for that same problem you could do 50+y=100. Then the (y) would be the variable.
3/y=5/36
y = 2x + 2
You solve one of the equation for one of the variables. For example, if the variables involved are "x" and "y", you might solve for "y". It doesn't really matter what variable you solve for first, so you can solve for whatever variable is easiest to solve. Then - assuming you got, for example, "y = 3x -1", in this example you would replace every "y" by "3x - 1" in the other equation or equations.
3y=ab. Divide by 3 to get y=ab/3
4
you have to solve for the variable for example. 4x + 2y = 8. you would solve for y. so you subtract the 4x and you do the same to both sides and you get 2y = -4x + 8. you then divide everything by 2 to get y by itself and you end up with y = -2x + 4
your equation is this... 2x < y + 7 Now solve for y... 2x - 7 < y Since you have two variable the most you can get out of (y) is the graph and the y-intercept. the y-intercept is y > -7
Assuming you meant to insert an = between xyy and 4, then xyy=4. Divide by x to get yy=4/x. yy is y^2, so y^2=4/x. Take the square root of both sides to get y=±√(4/x)
Solve the standard form for the dependent variable, commonly 'y'.
Minterms • A minterm is a special product of literals, in which each input variable appears exactly once. • A function with n variables has 2n minterms (since each variable can appear complemented or not) • A three-variable function, such as f(x,y,z), has 23 = 8 minterms: • Each minterm is true for exactly one combination of inputs: x'y'z' x'y'z x'yz' x'yz xy'z' xy'z xyz' xyz Minterm Is true when… Shorthand x'y'z' x=0, y=0, z=0 m0 x'y'z x=0, y=0, z=1 m1 x'yz' x=0, y=1, z=0 m2 x'yz x=0, y=1, z=1 m3 xy'z' x=1, y=0, z=0 m4 xy'z x=1, y=0, z=1 m5 xyz' x=1, y=1, z=0 m6 xyz x=1, y=1, z=1 m7