I will use "root" as a symbol for square root. I assume you want to get rid of the square root in the denominator; this will usually bring some square root into the numerator.
If you have the square root by itself, or as a factor, multiply numerator and denominator by this square root. Example:
3 / root(2) = 3 x root(2) / root(2) x root(2) = 3 x root(2) / 2.
If the square root is added or subtracted with something else, multiply with a "complement", as in the following example:
1 / root(2) + 5
The "complement" is the same expression, but changing the plus sign to a minus sign. Multiply numerator and denominator aby root(2) - 5:
root(2) - 5 / (root(2) + 5)(root(2) - 5)
= (root(2) - 5) / (2 - 25)
= (root(2) - 5) / -23
= -(root(2) - 5) / 23
It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).
This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.
You can get a decimal approximation with a calculator, with Excel, etc. But if you want to keep it as a square root, the "standard form" is considered to be one that has no square roots in the denominator. In this case, to get rid of the square root in the denominator, you multiply both numerator and denominator by the square root of 5, with the following result: 3 / root(5) = 3 root(5) / root(5) x root(5) = 3 root(5) / 5 That is, three times the square root of 5, divided by 5.
It represents the order of the root that needs to be calculated. A denominator of 2 means a square root. A denominator of 3 means a cube root. And so on.
The rules for "standard radical form" are that (a) there should be no perfect square within the radical sign; for example, square root of 12 is equal to square root of 4 x square root of 3 = 2 x square root of 3, and should be written as the latter; and (b) there should be no radical sign in the denominator. For example, if you have 1 / square root of 2, you multiply top and bottom by the square root of 2, to get a square root in the numerator, but none in the denominator.
Depends on the situation. You usually have to multiply numerator and denominator by some number or expression. Examples: 1 / square root of 2 Here, you have to multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3) Here, you have to multiply numerator and denominator by (square root of 2 - square root of 3).
It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).
That is called "rationalizing the denominator". It consists of multiplying the numerator and the denominator by specific terms, which include square roots. Examples:* If the denominator is root(2) (that is, the square root of 2), multiply numerator and denominator by root(2). * If the denominator is root(2) + root(3), multiply numerator and denominator by root(2) - root(3).
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
find the square root of the numerator and the square root of the denominator
This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.
An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).
Only if the square root of the numerator and the square root of the denominator are both rational numbers.
You can get a decimal approximation with a calculator, with Excel, etc. But if you want to keep it as a square root, the "standard form" is considered to be one that has no square roots in the denominator. In this case, to get rid of the square root in the denominator, you multiply both numerator and denominator by the square root of 5, with the following result: 3 / root(5) = 3 root(5) / root(5) x root(5) = 3 root(5) / 5 That is, three times the square root of 5, divided by 5.
its false apex :)
It represents the order of the root that needs to be calculated. A denominator of 2 means a square root. A denominator of 3 means a cube root. And so on.