0
Suppose a diver leaps from the edge of a cliff 80 feet above the ocean with an initial upward velocity of 8 feet per second How long will it take the diver to enter the water below?
Wiki User
∙ 10y ago
Assuming that acceleration dut to gravity is 32 ft/sec2 and that air resistance is insignificant, the answer is 2.5 seconds.
To show work, at 8 ft/sec v = at = 32 t
t = 1/4 second jumping up and v = 0 before free fall
s = 1/2 at^2 = 16t^2 = 16x.25 x .25 = 1 foot so diver free falls 81 feet
81 = 1/2 at^2 so t = 2.25 sec
2.25 + .25 = 2.5 sec
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What are the answers to 14.10 punchline Algebra book b marcy math works?
A diver springs from the edge of the ocean with an initial upward velocity of 8 ft/s. How long will it take the diver to reach the water?
How do you calculate height based on velocity and time?
I assume you refer to the formula distance = velocity x time. If an object moves upward, the distance would become the height.
Slope of a line that slants upward?
If the line slants upward (going towards the right), then the slope is positive.
if the parabola open upward a is?
positive.
What is lying face upward called?
supine
What object shoots upward with an initial velocity of 6 meters per second?
anything shot up with that initial velocity. There isn't anything in specific.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
What is the initial direction on the projectile's velocity?
its upward at some specified angle
A girl throws a tennis ball upward with an initial velocity of 4 meters per second. What is the maximum displacement of the ball?
0.82 metres.
A girl throws a tennis ball upward with an initial velocity of 4 meters per second . What is the maximum displacement of the ball?
0.82 metres.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
How is distance travel by particle projected vertically upward with initial velocity 25 meter per seconds is 2.5 mt in 3rd second of motion?
i
How high can a ball go?
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
When a ball is thrown vertically upward at initial velocity of 15 meter per second Find the position and velocity after 1.0 second and 40 second after leaving your hand?
1 sec : position = 10.1 metres above your hand, velocity = 5.2 ms^-1.40 sec : position = 7240 metres below your hand, velocity = 377 ms^-1 downwards.
A rocket of initial mass m0 is shot vertically upward Assume that the motion occurs under constant gravitational acceleration g Let the initial velocity of the rocket on the surface of the earth be?
the initial velocity of the rocket is zero.
When will a stone return to the groun if it is thrown upward with an initial velocity of 16ms?
After just over three and a quarter seconds.
To celebrate a victory a pitcher throws her glove straight upward with an initial speed of 6.2 How long does it take for the glove to return to the pitcher?
I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
