If y varies with x, then there cannot be an inverse variation between x and y!
2=8/4 the constant is 8 y-k/x i think.
xy = K so K = 21
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
xY = 6.
if x varies inversely as y then xy is a constant (k) eg if x doubles as y halves then examples are: x = 6, y = any then k = 6y when x = 12, y = any/2 then k = 12/2 times any ie 6y.
If you have already determined whether your particular model is direct or inverse variation, then the two models will follow the following functions: Direct: y=kx ---y is always expressible as a constant multiple of x, meaning it varies directly with x by a factor of k Inverse: y=k/x ---y is always expressible as a constant multiple of the inverse of x (1/x). It varies directly with the inverse of x by a factor of k.
2=8/4 the constant is 8 y-k/x i think.
x+y=8 y=-x+8 is not an inverse variation. However, y=8/x is an inverse variation or y varies inversely as x.
Direct variation is the ratio of two variable is constant. Inverse variation is when the product of two variable is constant. For example, direct variation is y = kx and indirect variation would be y = k/x .
xy = K so K = 21
Both are variations of certain kinds of equations. X=kY is a direct variation since X varies directly as Y and k is the constant of variation. X=k/Y is an inverse variation where X varies inversly as Y and k is the constant of variation. Both of these variations are also functions.
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
xY = 6.
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 28 ) when ( x = 7 ), we can substitute these values into the equation to find ( k ): [ 28 = k(7) \implies k = 4. ] Thus, the equation of variation is ( y = 4x ).
2
1
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given the values ( y = 80 ) when ( x = 40 ), we can find ( k ) by substituting these values into the equation: ( 80 = k(40) ). Solving for ( k ) gives ( k = 2 ). Therefore, the equation of variation is ( y = 2x ).