Yes. Any number, or expression, is equal to itself. An equation such as:x + 5 = x + 5
is true for ANY value of "x".
Oh, dude, it's like this: all quadratic equations are polynomials, but not all polynomials are quadratic equations. A quadratic equation is a specific type of polynomial that has a degree of 2, meaning it has a highest power of x^2. So, like, all squares are rectangles, but not all rectangles are squares, you know what I mean?
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
You set the derivative equal to zero and solve the equation. For example y = x^2 + 5x +7 is the equation of a parabola. dy/dx = 2x +5. Setting 2x +5 = 0 then x = -5/2. When x = -5/2 y = 3/4. This is the minimum. We know it's a minimum and not a maximum because when x is large y is large.
For the equation: x2+4x-5 = 0 Factoring yields: (x+5)(x-1) = 0 The zero identity states that setting these factors individually equal to zero will yield valid solutions to this equation. x+5 = 0, x = -5 x-1 = 0, x = 1 So the values x=-5 and x=1 solve this equation. For the mathematical function: y = x2+4x-5 The derivatives for this function are as such: y' = 2x+4 y'' = 2 The second derivative is a constant positive number (2), so it is always positive. Since the second derivative is always positive, its curvature is always concave upward.
an equation
You can't answer this question without setting that expression equal to something. Right now, your equation reads 4x+15=?, essentially created a system of two variables with only one equation, which is unsolvable.
When there is no equal sign in the equation, the expression is typically not solvable for a specific value of x. Instead, it may represent a relationship or function where x can take on various values. In this case, you would treat the expression as a function or inequality and analyze its properties or solutions based on the context provided. If additional information or constraints are given, you can use algebraic manipulation or graphing techniques to explore the possible values of x within those constraints.
an equation
The roots of an equation in two variables is calculated by setting the dependent variable, y, equal to 0 and then solving the resulting equation for the independent variable, x. The procedure for solving the equation in x will depend on the nature of the equation.
As written this is not a graphable thing. I does not represent a graphable equation because there is no "=" sign. Whatever the equation might be, the x intercept is found by setting y=0, which leaves you with an equation for x, which is the intercept.
When the denominator is equal to zero, the expression is undefined. Close to those places, the expression tends towards plus infinity, or minus infinity. In other words, setting the denominator to zero will tell you where there are vertical asymptotes.
As in "f*cking the dog" - the act of being lazy, typically used in a workplace setting.
The Greek expression for cheers is Yama's. This is used when drinking in a group setting. Everyone raises their glasses and says Yama's.
You can write an equation that works in forward and reverse by setting the same variables on either side. Alternatively you can set offsetting variables on each side which will also create the same results.
You could try setting the function equal to zero, and finding all the solutions of the equation. Just a suggestion.
The main methods for balancing a chemical equation are inspection, trial and error, and algebraic methods. Inspection involves visually balancing the equation by adjusting the coefficients of the compounds. Trial and error involves systematically changing coefficients until the equation is balanced. Algebraic methods involve setting up and solving a system of linear equations to determine the coefficients.