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For the equation:

x2+4x-5 = 0

Factoring yields:

(x+5)(x-1) = 0

The zero identity states that setting these factors individually equal to zero will yield valid solutions to this equation.

x+5 = 0, x = -5

x-1 = 0, x = 1

So the values x=-5 and x=1 solve this equation.

For the mathematical function:

y = x2+4x-5

The derivatives for this function are as such:

y' = 2x+4

y'' = 2

The second derivative is a constant positive number (2), so it is always positive. Since the second derivative is always positive, its curvature is always concave upward.

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