If the diameter is 12mm then the radius is 6mm. The area of a circle is pi X r2. Therefore pi X 36 mm2 = about 113.0973 mm2 = area of the circle. Don't forget units!! pi is about 3.1416.
6mm would be 0.6 cm because 10mm is 1cm and 1 cm -4 would be 0.6
In terms of numerical value, 6MM is larger than 3MM. The "MM" in this context stands for million, so 6MM represents 6 million while 3MM represents 3 million. Therefore, 6MM is double the value of 3MM.
Four millimeters (mm) is equivalent to one centimeter (cm) because there are 10 millimeters in one centimeter. Therefore, when you have 4 millimeters, you have 4/10 of a centimeter, which simplifies to 0.4 centimeters. So, 4mm is equal to 0.4cm.
20%
d = 2r = 12 mm
Area of a circle = pi*r2 , where pi = 3.14 and r is the radius of the circle. We have diameter(d) = 12mm so, radius(r) = d/2 = 6mm On putting the values we get Area = 3.14*62 = 3.14*36 = 113mm2
Area = 113.1mm2
If the diameter is 12mm then the radius is 6mm. The area of a circle is pi X r2. Therefore pi X 36 mm2 = about 113.0973 mm2 = area of the circle. Don't forget units!! pi is about 3.1416.
six tenths 1cm = 10mm 0.6cm = 6mm 0.6 = 6/10
Area = pi*32 = 28.274 square mm to 3 d.p.
A = pi r^(2) r = 6mm pi ~ 3.14 A = 3.14 *(6mm)^(2) A = 3.14 * 36 mm^(2) A = 113.04 mm^(2)
6mm would be 0.6 cm because 10mm is 1cm and 1 cm -4 would be 0.6
An ordinary pencil is one example.
3.85
A cent (penny) is circular so the "greatest distance" is simply its diameter. Since 1858, all US cents have had a diameter of 19.05 mm.
As one of the contributors noted, I would like to also state that if these are home works that students are asked to do by their teachers (school work) it defeats the purpose of the homework. Instead of solving the problem I will give hints. Staff who monitor and moderate this site, please give contributors some guidelines please. Find the area of the 20cm diameter circle. Divide it by the area of the 6mm diameter circle. If you get a whole number, that is the answer. If not round it down to the nearest whole number.