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Let the length be 3x+2 and the width be x:

(3x+2)*x = 33

3x2+2x = 33

3x2+2x-33 = 0

Solve as a quadratic equation:

(3x+11)(x-3) = 0

Therefore: x = -11/3 or x = 3 The dimensions can't be negative so x must = 3

So: length = 11 feet and width = 3 feet

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Q: The area of a rectangle is 33 sq ft If the length is 2 more than three times the width find the length and width?
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