Let the length be 3x+2 and the width be x:
(3x+2)*x = 33
3x2+2x = 33
3x2+2x-33 = 0
Solve as a quadratic equation:
(3x+11)(x-3) = 0
Therefore: x = -11/3 or x = 3 The dimensions can't be negative so x must = 3
So: length = 11 feet and width = 3 feet
length times width
call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x
The perimeter of a rectangle is equal to 2*length + 2* width. In this case, we will say 2x + 2y = p = 48. Since the length is equal to 3 times the width, the equation now becomes p = 6*y + 2*y, or just p = 8y. Now since p =48, y must equal 6. And since the length is three times the width (y), the length is 18.
The area of a rectangle is the length times the width. Example: Let's say a problem asked you : What is the area of a rectangle with a length of 5 cm and a width of 7 cm. Solution: All you have to is multiply 7 times 5 = 35 square cm
Area of a rectangle is width times lenght. 14m in lenght (times) 5m in width = 70m2
9
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
Width: 8.5 Length: 25.5
the length is equal to 160,083
dont is answer
It is the area of the rectangle which is length times width
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
63 feet
15 feet.
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
A = lw Area of a rectangle = length times width
64 meters