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The curve y ax 2 plus bx plus 12 has a stationary point 1 13 find a and b?
Wiki User
β 9y ago
The point (1, 13) lies on y = ax^2 + bx + 12
So the coordinates of the point satisfy the equation.
13 = a + b + 12
=> a + b = 1 .. .. .. .. .. .. .. .. .. (1)
The stationary point of the curve is reached when dy/dx = 0: that is 2ax + b = 0
at (1, 12) this gives 2a + b = 0 .. .. .. (2)
Solving (1) and (2) gives a = -1, b = 2
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β 9y ago
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