A rectangle.
Note: a square is a regular rectangle where all sides are equal; in this case not only are the diagonals equal and bisect each other, they also bisect perpendicularly, that is at 90o to each other.
i think its a trapezoid...
always
The missing word is "bisect".
true
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
diagonals.
square
trapezoid
a trapezoid
i think its a trapezoid...
I think this is impossible the diagonals of a four sided figure will cross
It could be a square, but consider the following congruent & perpendicular 'diagonals of a quadrilateral (you will have to connect the endpoints of the diagonals, yourself, as it cannot be drawn in text): . _|___ . | . | . | If the two diagonals, also bisect each other, then it's a square, otherwise it is not.
True
True
Yes, they do. Also, they are congruent to each other. * * * * * They do bisect each other but they are not congruent.
The diagonals of a rectangle are congruent and they bisect each other.
always