i think its a trapezoid...
Quadrilaterals do not bisect each other. They could in special cases. In parallelograms (types of quadrilaterals), the diagonals bisect each other.
Parallelogram and a rectangle
trapeziums,kites,rectangles,parallelogramsHere are a few that I could think of:(quadrilateral: polygon with four sides)parallelogram: quadrilateral with both pairs of opposite sides paralleltrapezoid: quadrilateral with just one pair of opposite sides parallelrectangle: parallelogram with four right anglesrhombus: parallelogram with four congruent sidessquare: parallelogram with four right angles and four congruent sides
Is rectangle and any parallelogram not square or rhombus
"Bisect" means to divide a shape into 2 equal parts. One case where 2 intersecting quadrilaterals bisect each other, is when they are both rectangles, twice as long as they are wide. They could intersect to overlap in way that made 3 squares. One of the squares would be in common. This could be done with the rectangles either lined up, or at right angles.This can also work with 2 identical (or mirrored) parallelograms, where the longer sides are exactly twice as long as the short sides. They could overlap at the ends (in 2 ways, depending whether they are identical or mirrored) to have a rhombus in common. Rectangle, rhombus and square are special cases of parallelogram.When putting questions from school into Answers, be sure to use the same wording. Perhaps "bisect" was not the word.2 quadrilaterals that are of different sizes can not bisect each other.Some quadrilaterals have sides which are all of different lengths.Kite shapes are also quadrilaterals.
It could be a square, but consider the following congruent & perpendicular 'diagonals of a quadrilateral (you will have to connect the endpoints of the diagonals, yourself, as it cannot be drawn in text): . _|___ . | . | . | If the two diagonals, also bisect each other, then it's a square, otherwise it is not.
the anser to this question is a trapiezuim as it could have right angles and its diagonals definatly do not bisect each other
Since the diagonals of a rhombus are perpendicular between them, then in one forth part of the rhombus they form a right triangle where hypotenuse is the side of the rhombus, the base and the height are one half part of its diagonals. Let's take a look at this right triangle.The base and the height lengths could be congruent if and only if the angles opposite to them have a measure of 45⁰, which is impossible to a rhombus because these angles have different measures as they are one half of the two adjacent angles of the rhombus (the diagonals of a rhombus bisect the vertex angles from where they are drawn), which also have different measures (their sum is 180⁰ ).Therefore, the diagonals of a rhombus are not congruent as their one half are not (the diagonals of a rhombus bisect each other).
Quadrilaterals do not bisect each other. They could in special cases. In parallelograms (types of quadrilaterals), the diagonals bisect each other.
Any quadrilateral other than a square or kite could have diagonals meeting at 30 degrees.
They could be congruent, but not necessarily. It cannot be assumed that they are.
False. It could be a rhombus.
Because it's irregular, they could be anything!
False. Could be a trapezoid.
No you could have Square, Rectangle, Rhombus, Parallelogram
It could also be a square or a rhombus.
Parallelogram and a rectangle