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Yes, and it's 9 times the sum of the digits. Think of the first number as 10x + y, then its reverse is 10y - x. Subtracting gives 9x - 9y ie 9 (x - y), a multiple of 9. For example, taking 7 and 1 as the numbers, then 71 - 17 = 9 (7 - 1) ie 9 x 6 = 54 QED

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Q: The difference between a 2-digit number and its reverse is always a multiple of 9?
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