Oh, isn't that just a happy little math problem we have here? Let's give it some color and see what we find. If the difference of the two numbers is 32 and their sum is 158, we can create a simple system of equations to solve for the numbers. One number would be 95 and the other would be 63. Just like that, we've painted a beautiful solution!
158 - 32 = 126, 126/2 = 63, 63 + 32 = 95 so your numbers are 63 & 95
32 - 22 + 10 32 + 22 = 54
13 and 19
Let's denote the two numbers as x and y. We know that the sum of the two numbers is 4, so we can write the equation x + y = 4. We also know that their product is -32, so we can write the equation xy = -32. By solving these two equations simultaneously, we can find the two numbers. The numbers are 8 and -4.
1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
The sun of two num is 32 and the difference is 10. What are the numbers?
158 - 32 = 126, 126/2 = 63, 63 + 32 = 95 so your numbers are 63 & 95
28 and 32
18 and 32
32 and 19
18 and 32
the 2 numbers are 51 and 19
The sun of two num is 32 and the difference is 10. What are the numbers?
32 - 22 + 10 32 + 22 = 54
the two numbers are 99 and 67. god I'm on fire today.
The numbers 32 and 1 (32 x 1 = 32) sum to 33. The numbers 4 and 8 (4 x 8 = 32) sum to 12 The numbers 2 and 16 (2 x 16 = 32) sum to 18. There are no other factors which are integers, so 32 and 1 is the answer.
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).