One quarter-Apex
Half-life is 5.27 years; 21 / 5.27 = 3.99, or almos 4 half-lives; (1/2)4 = 1/16.
It becomes half of what the original area is.
25/100 = 1/4 of the original sample. The "half-life" must pass twice, yielding (1/2) x (1/2) = 1/4 of the original sample. The half-life of Carbon-14 is listed as ( 5,730 ± 40 ) years. Twice that is ( 11,460 ± 80 ) years
3/8
Don "Half Pint" Santos, original Immature band member, is 28 yrs old.
After 1 year, 50% of the original amount of cobalt-60 will remain. This means that 50% will decay and 50% will be left. After 4 years, 6.25% of the original amount (50% of 50%) of cobalt-60 will remain.
After one half-life, 50% (or half) of the original uranium remains.
After 14 years, 1/16th of the original amount of cobalt-60 will remain, because 14 years is equivalent to 2.64 half-lives of cobalt-60 (14 years / 5.3 years/half-life). Each half-life reduces the amount of cobalt-60 by half, so after 2.64 half-lives, the original amount will be reduced to 1/2^2.64 which is approximately 1/16th.
After one half-life, approximately 50% of the original sample of radioisotope remains. This means that half of the original radioisotope has decayed into a stable form.
1/8 of the original amount remains.
One eighth remains.
At the end of a second half-life, one-fourth (25%) of the original isotope remains. This is because each half-life halves the amount of the isotope present.
The half-life of cobalt-57 is about 271.74 days.
Half the original amount.
The half-life of Cobalt-60 is about 5.27 years. This means that in this time, half of the original amount of Cobalt-60 will have decayed into other elements. It is commonly used in medical and industrial applications due to its radioactive properties.
After one half-life, half of the radioactive sample remains. This means that the remaining fraction is 1/2 or 0.5 of the original sample.
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.