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From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.

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Q: The length of a rectangle is twice its width If the area of the rectangle is less than 50 square meters what is the greatest width of the rectangle?
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