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Q: The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?

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Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal

The diagonal of a square 2.0 meters on a side is: 2.828 meters.

If the area is 117 square meters and the width is 9 meters we can find the length by dividing: 117 / 9 = 13 The length is 13 meters

if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units

area of a rectangle = length * width. Rearranging, we have width = area / length. Therefore, the width of the rectangle = 31.2 [m2] / 6 [m] = 5.2 [m] ========================

Related questions

-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.

To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).

The perimeter of this square is 56.569 meters.

If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square

You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.

Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal

Length of rectangle: 240/15 = 16 meters

It is square root of (length square + breadth square) (l2 + b2 ) 1/2

If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.

You draw a rectangle that has a diagonal which length is equal to twice the length of the side of the square.

The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

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