100-3(1) = 100-3 = 97
100-3(2) = 100-6 = 94
100-3(3) = 100-9 = 91
Over here N is the first 3 terms, 1, 2, and 3.
4,8,12,16,20
6
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
It is the description of a rule which describes how the terms of a sequence are defined in terms of their position in the sequence.
5, 11, 17, 23, 29
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
2,1,0 is th sequence of its terms
The first four terms are 3 9 27 81 and 729 is the 6th term.
4,8,12,16,20
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
no clue
6
1, 16, 81, 256 14641 is the 11th term.
To find the first three terms of a sequence where the fifth term is 162, we can assume the sequence follows a specific pattern, such as an arithmetic sequence. For example, if we let the first term be ( a ) and the common difference be ( d ), the fifth term can be expressed as ( a + 4d = 162 ). By choosing ( a = 82 ) and ( d = 20 ), the first three terms would be 82, 102, and 122. However, many sequences could satisfy the condition, so the terms can vary depending on the assumed pattern.
I try to be psychic, but fail miserably. If you could give me a clue, like the first few terms of the sequence, I could have a go at giving you the 77th term.
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.