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What is the 5th term of the sequence which has a first term of 17?
That depends what the pattern of the sequence is.
What are the first 5 terms of 16 - 3n?
taking the 1st term as n=1 the 2nd term as n= 2 etc then the first 5 terms of 16-3n are : 1st : 16-3 = 13 2nd : 16-6 = 10 3rd : 16-9 = 7 4th: 16-12 = 4 5th : 16-15 = 1 hope this helps
How to find the 5th term in an arithmetic sequence using the explicit rule?
Nth number in an arithmetic series equals 'a + nd', where 'a' is the first number, 'n' signifies the Nth number and d is the amount by which each term in the series is incremented. For the 5th term it would be a + 5d
What is the power function from this data x 1 2 3 4 5 6 y2 6 10 15 23 30?
It will have to be a very complex power function because the are not increasing steadily. The increase between the 5th and 6th term is smaller than that between the 4th and 5th terms.
What is the term to describe every 5th year?
quinquennial
The 7th term of an arithmetic progression is 6 The sum of the first 10 terms is 30 Find the 5th term of the progression?
2
What number is earth in terms of size?
earth is 5th number in term of size
What is the 5th term of the sequence which has a first term of 17?
That depends what the pattern of the sequence is.
What are the first 5 terms of 16 - 3n?
taking the 1st term as n=1 the 2nd term as n= 2 etc then the first 5 terms of 16-3n are : 1st : 16-3 = 13 2nd : 16-6 = 10 3rd : 16-9 = 7 4th: 16-12 = 4 5th : 16-15 = 1 hope this helps
How many terms did Richard J Daley serve?
Richard J. Daley served the following: Terms of Office 1st term: 1955-1959 2nd term: 1959-1963 3rd term: 1963-1967 4th term:1967-1971 5th term: 1971-1975 6th term: 1975-1976 (died in office) see also, Chicago's Mayors, Chicago Public Library at: ChiPubLib
What does the payment term net 5th of 3rd month mean?
The payment term "net 5th of 3rd month" means that payment is due on the 5th day of the third month following the invoice date. For example, if the invoice is dated in January, the payment would be due on March 5th. This term gives the buyer additional time to settle the invoice compared to standard net payment terms, which typically require payment within a month.
How to find the 5th term in an arithmetic sequence using the explicit rule?
Nth number in an arithmetic series equals 'a + nd', where 'a' is the first number, 'n' signifies the Nth number and d is the amount by which each term in the series is incremented. For the 5th term it would be a + 5d
What formula represents the partial sum of the first n terms of the series 5 10 15 20 25?
The series given is an arithmetic progression consisting of 5 terms with a common difference of 5 and first term 5 → sum{n} = (n/2)(2×5 + (n - 1)×5) = n(5n + 5)/2 = 5n(n + 1)/2 As no terms have been given beyond the 5th term, and the series is not stated to be an arithmetic progression, the above formula only holds for n = 1, 2, ..., 5.
What is the fifth Nth term of 10-N squared?
2500, 100n2Restate the question: what are the 5th and nth term of (10n)2?If this is not your question, please clarify and resubmit the question.Assuming the first term is when n=1, then the 5th term is (10x5)2 = (50)2 =2500.The nth term would be just (10n)2, although you could expand and simplify to get (102)(n2) = 100n2.
Which president was the one and only president to take the oath of office for a third term?
FDR was the only president to server more than 2 terms so it must be him, Franklin died of polio at the begining of his 4th or 5th term i don't remember which
Q 5th term of a GP is 2 then product of its 9 terms is?
I'll try to answer the question, "If the 5th term of a geometric progression is 2, then the product of its FIRST 9 terms is --?" Given the first term is A and the ratio is r, then the progression starts out... A, Ar, Ar^2, Ar^3, Ar^4, ... So the 5th term is Ar^4, which equals 2. The series continues... Ar^5, Ar^6, Ar^7, Ar^8, ... Ar^8 is the 9th term. The product P of all 9 terms is therefore: P = A * Ar * Ar^2 *...*Ar^8 Collect all the A's P = (A^9)*(1 * r * r^2 ...* r^8) P = A^9 * r^(0+1+2+...+8) There's a formula for the sum of the first n integers (n/2)(n+1), or if you don't know just add it up. 1+2+...+8 = 36 Therefore P = A^9 * r^36 Since 36 is a multiple of 9, you can simplify: P = (Ar^4)^9 Still with me? Remember that Ar^4=2 (a given fact). So finally P = 2^9 = 512. Cute problem.
What is the 5th term of 3 6 12?
Each term seems to be double of the previous number starting with 3. Hence 4th term = 24 and 5th is 48
