True for an obtuse triangle!
The orthocenter is the point where the altitudes of a triangle intersect. An orthocenter lies outside of a triangle only when the triangle is obtuse. If a triangle is acute, the orthocenter lies inside of the triangle.
Orthocenter My improvement: The three angle bisectors will intersect at a point called the incenter. At this point it also the center of the largest possible circle within the triangle. Since a circle has a center point, this point within the triangle is called the incenter. The three heights of a triangle will meet at a special point called the orthocenter.
Since the intersection of the perpendicular bisectors of a triangle is the center of the inscribed circle (we call it the centroid of a triangle), the answer is no.
No, since an equilateral triangle has three congruent angles of 60 degrees, and a right triangle must have an angle of 90 degrees. However, a right triangle may be an isosceles triangle.
NO, because and acute triangle is less than 90 degree and if u want a horse to fit u need a triangle bigger than 90 degree so u need an obtuse triangle instead of a acute triangle
The orthocenter is the point where the altitudes of a triangle intersect. An orthocenter lies outside of a triangle only when the triangle is obtuse. If a triangle is acute, the orthocenter lies inside of the triangle.
The orthocenter of a triangle may lie outside the triangle because an altitude does not necessarily intersect the sides of the triangle.
The orthocenter of a triangle may lie outside the triangle since the ___altitude___ may not intersect any side of the triangle. * * * * * No. One of the altitudes must intersect the side opposite it and so it is not correct to say ANY side of the triangle.
Not normally
Orthocenter My improvement: The three angle bisectors will intersect at a point called the incenter. At this point it also the center of the largest possible circle within the triangle. Since a circle has a center point, this point within the triangle is called the incenter. The three heights of a triangle will meet at a special point called the orthocenter.
Oh, dude, the orthocenter of a triangle got its name because it's where the altitudes of the triangle intersect. It's like the center of gravity for altitudes, you know? So, "ortho" means perpendicular in Greek, and since the altitudes are perpendicular to the sides of the triangle, they just called it the orthocenter. Cool, right?
Since the intersection of the perpendicular bisectors of a triangle is the center of the inscribed circle (we call it the centroid of a triangle), the answer is no.
none. A triangle, in standard 2 dimensions cannot have any parallel sides. Let's show without going into formal proof. Let's say that you try to make a triangle with 2 parallel sides. -------------side a------------- |C | | |side b | | |A -------------side c--------------- Side a & b intersect at vertex C. Side b & c intersect at vertex A, and since sides a & c are parallel, they will never intersect, so there is no third vertex, so it's not a polygon, much less a triangle.
Since the lines that intersect are the equations, if they intersect once they have one solution.
It is a plotted area outside of Bermuda whose boundaries form the shape of a triangle. Therefore, in a way, it is truly a triangle. It also isn't really a triangle though, since it has invisible boundaries.
If you wanted to find the distance, you would just add 1.2+1.2+1.2=3.6. Since the triangle is equilateral, all sides will be equal.
They are skew line. Skew line are two lines that do not intersect but are not parallel.Another definition is skew lines are straight lines that are not in the same plane and do not intersect.Either way, skew lines are the answer to your question since they are noncoplanar and do not intersect.