P = 2(L + W) = 236
L + W = 118
W + 64 + W = 118 (since L = W + 64)
2W = 54
W = 27 inches
and then L = W + 64 = 91 inches
112 inches
Perimeter = 2*(Length + Width) = 2*(16 + 12) = 2*28 = 56 inches
Perimeter = 32 inches. Area = 55 square inches.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
The perimeter is 11 + 5 + 13 = 29 inches.
Length + width = half perimeter = 100". Length is 98", width is 2"
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
The perimeter is 60 inches
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
28 inches
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
Its length is 18 inches
112 inches
Do-it-in-your-head method:Length + width is half the perimeter, ie 76 inches;76 - 36 = 40;Half of 40 is 20: this is the width;20 + 36 = 56: this is the length.Job done.