L + W = 28/2 = 14
L = 3 + 3W, so 3 + 3W + W = 14 ie 4W = 11
so width is 2¾" and length is 11¼"
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
112 inches
Perimeter = 2*(Length + Width) = 2*(16 + 12) = 2*28 = 56 inches
Perimeter = 32 inches. Area = 55 square inches.
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
That would be 3 x 9 inches.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
Length = 3.5 inches and Width = 2.5 inches Check: 2(3.5+2.5) = 12 inches
The perimeter is 60 inches
You forgot to put in the length of the rectangle's perimeter.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
28 inches