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The perimeter of a rectangular playing field measures 504 yards Its length is 9 yards shorter than twice its width Find the area?
14355 yds2
Let l represent the length and w the width. Perimeter equals 2*l+2*w. From the information in the problem, we have two equations and two unknowns:
2l+2w=504
l=2w-9
Substitute l from the second equation into the first equation and solve for w:
2(2w-9)+2w=504
4w-18+2w=504
6w-18=504
6w=522
w=522/6=87
Now, substitue w=87 into the second equation above to find l:
l=2*87-9=165
With the length and width determined, we can find the area:
Area = l*w=165*87=14355 yds2
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