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14355 yds2

Let l represent the length and w the width. Perimeter equals 2*l+2*w. From the information in the problem, we have two equations and two unknowns:

2l+2w=504

l=2w-9

Substitute l from the second equation into the first equation and solve for w:

2(2w-9)+2w=504

4w-18+2w=504

6w-18=504

6w=522

w=522/6=87

Now, substitue w=87 into the second equation above to find l:

l=2*87-9=165

With the length and width determined, we can find the area:

Area = l*w=165*87=14355 yds2

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Q: The perimeter of a rectangular playing field measures 504 yards Its length is 9 yards shorter than twice its width Find the area?
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