7b = 63 Divide both sides by 7:- b = 9
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
The asterisk * A * B = the product of A and B 2 * 7 = 14
10a + b = 7(a + b) 10a + b = 7a + 7b 3a = 6b a = 2b (2,1), (4,2), (6,3), and (8,4) meet these requirements. So the numbers that are solutions are 21, 42, 63, and 84.
95
7b = 63 Divide both sides by 7:- b = 9
your equation is this 9N=63 9N/9=63/9 N=7 your answer is 7
a. 63
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
LCM(a,b) = (ab)/(GCF(a,b)) 63 factors to [3 3 7] 15 factors to [3 5] common factors: [3] 63 * 15 / 3 = 315 ■
(A1) The dot product of two vectors is a scalar and the cross product is a vector? ================================== (A2) The cross product of two vectors, A and B, would be [a*b*sin(alpha)]C, where a = |A|; b = |B|; c = |C|; and C is vector that is orthogonal to A and B and oriented according to the right-hand rule (see the related link). The dot product of the two vectors, A and B, would be [a*b*cos(alpha)]. For [a*b*sin(alpha)]C to equal to [a*b*cos(alpha)], we have to have a trivial solution -- alpha = 0 and either a or b be zero, so that both expressions are zeroes but equal. ================================== Of course one is the number zero( scalar), and one is the zero vector. It is a small difference but worth mentioning. That is is to say if a or b is the zero vector, then a dot b must equal zero as a scalar. And similarly the cross product of any vector and the zero vector is the zero vector. (A3) The magnitude of the dot product is equal to the magnitude of the cross product when the angle between the vectors is 45 degrees.
If a, b & c are prime numbers then their LCM is equal to their product i.e. a x b x c.Here, 5, 7 and 13 are prime numbers.Therefore, LCM(7,5,13) = 7 x 5 x 13 = 455.
The cross product must be equal. Two fractions: A/B and C/D are equal if (and only if) A*D = B*C
The asterisk * A * B = the product of A and B 2 * 7 = 14
10a + b = 7(a + b) 10a + b = 7a + 7b 3a = 6b a = 2b (2,1), (4,2), (6,3), and (8,4) meet these requirements. So the numbers that are solutions are 21, 42, 63, and 84.
b = 7 (74 = 2,401)
area of rectangle=L*B 9*7 =63