a=7
b=9
ab=?
ab is the multiplication of a & b
there fore the value of ab=7*9=63
We suspect that 'A' is not equal to 7 9, but that (7, 9) arethe coordinates of 'A'. Same for 'B'.If that's true, then the two points are 5 units apart.
5 [3-4-5 triangle]
BS
7b = 63 Divide both sides by 7:- b = 9
A = 1, B = 9
Using the distance formula the length of ab is 5 units
15
We suspect that 'A' is not equal to 7 9, but that (7, 9) arethe coordinates of 'A'. Same for 'B'.If that's true, then the two points are 5 units apart.
5 [3-4-5 triangle]
5 [3-4-5 triangle]
The answer depends on the value of B.
B is (-5, 9).
Using the distance formula the length of ab is 5 units
Factorising -x2 + 7x + 18: (a - x)(x + b) = -x2 + (b - a)x + ab so ab = 18, b - a = 7 giving a = 2, b = 9: (2 - x)(x + 9)
It is: (9+5)/2 and (8+2)/2 which is 7 and 5 Midpoint: (7, 5)
BS
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)