odd x even = even
(2n + 1)(2n)
= 2[n(2n + 1)] let n(2n + 1) = t
= 2t (even)
No, the product will always be even.
The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
No such numbers exist; the product of two odd numbers is always odd.
When multiplied together, an odd number and an even number will always produce an odd number. Two consecutive numbers consist of one odd number and one even number, so their product is always an odd number. N-n-n-no! Any number multiplied by an even number yields an even product. Ever;y even number can be expressed as 2*M for some M. If we multiply 2*M by Y, the product is 2*M*Y = 2*(M*Y) which is even. So the right answer is: They don't! The product of two consecutive numbers is always even. Regards, Bill Drissel
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
It will alway be even, because it will always be the product of an odd and an even number, which is always even.
No, the product will always be even.
yes
The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times odd is always odd.
No such numbers exist; the product of two odd numbers is always odd.
When multiplied together, an odd number and an even number will always produce an odd number. Two consecutive numbers consist of one odd number and one even number, so their product is always an odd number. N-n-n-no! Any number multiplied by an even number yields an even product. Ever;y even number can be expressed as 2*M for some M. If we multiply 2*M by Y, the product is 2*M*Y = 2*(M*Y) which is even. So the right answer is: They don't! The product of two consecutive numbers is always even. Regards, Bill Drissel
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
No two consecutive numbers have a product that is an even number. Any two consecutive numbers include one odd number and one even number. The product of one odd number and one even number is always an odd number.
There are 3 cases: An even number time an even number such as 2*6=12 is always even. Proof: Since even numbers can be expressed as 2*X and 2*Y, their product is 4xy which is even. An even number times an odd number (same as odd times even) such as 2*3=6 is always even. Proof: 2X represents an even number and 2Y+1 represents an odd number. Their product is 4XY+2X=2(2XY+X), which is even. An odd number times an odd number such as 11*11=121 is always odd. Proof: Let 2X+1 and 2Y+1 be the two odd numbers. Their product is 4XY+2X+2Y+1 = 2(2XY+X+Y)+1, which is odd. Summary: the product of two numbers is always even unless the two numbers are both odd.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
The product of two odd numbers is always odd.