odd x even = even
(2n + 1)(2n)
= 2[n(2n + 1)] let n(2n + 1) = t
= 2t (even)
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No, the product will always be even.
The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
No such numbers exist; the product of two odd numbers is always odd.
When multiplied together, an odd number and an even number will always produce an odd number. Two consecutive numbers consist of one odd number and one even number, so their product is always an odd number. N-n-n-no! Any number multiplied by an even number yields an even product. Ever;y even number can be expressed as 2*M for some M. If we multiply 2*M by Y, the product is 2*M*Y = 2*(M*Y) which is even. So the right answer is: They don't! The product of two consecutive numbers is always even. Regards, Bill Drissel
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.