Easy. The quotient is the answer to a division problem. Say 8 divided by 2 = 4. 4 is the quotient as it is the answer to the question. What is the quotient of 132 divided by 11? We work it out - 132 divided by 11 = 12 Therefore 12 is our quotient. Hope I helped :D
Suppose the two fractions are b/f and c/d.Then (b/d)/(c/d) = (b/d)*(d/c) = (b*d)/(c*d) = b/d.
If you mean 36 divided by 3 then it is 12
No. is it not a, b,c, or d.
Nothing can be Divided to 0
Easy. The quotient is the answer to a division problem. Say 8 divided by 2 = 4. 4 is the quotient as it is the answer to the question. What is the quotient of 132 divided by 11? We work it out - 132 divided by 11 = 12 Therefore 12 is our quotient. Hope I helped :D
Suppose the two fractions, in their simplest form, are a/b and c/d, that is to say, a and b have no common factors, and neither do ca nd d. You want to find the quotient: (a/b) / (c/d). Now, dividing by (c/d) is the same as multiplying by (d/c). So the required quotient is the same as (a/b) * (d/c) or (a*d)/(b*c) . Multiply a and d for the numerator, b abd c for the denominator (after eliminating any factors that are common to a and c, and to b and d). That is your answer.
d2/(d - c) + c2/(c - d) = d2/(d - c) - c2/(d - c) = (d2 - c2)/(d - c) = (d + c)(d - c)/(d - c) = d + c
A quotient is the result of division. (7 - d)/5 will lead to a quotient.
#include<stdio.h> void main() { int a,b,c; printf("enter value of a and b:"); scanf("%d %d",&a,&b"); c=a+b; printf("sum is %d",c); c=a*b; printf("\n product is %d"c); c=a-b; printf("difference is%d",c); c=a/b; printf('quotient is%d",c); getch(); }
Suppose the two fractions are b/f and c/d.Then (b/d)/(c/d) = (b/d)*(d/c) = (b*d)/(c*d) = b/d.
If you mean 36 divided by 3 then it is 12
Suppose you have the improper fraction c/d where c > d > 0.Divide c by d so that c = q*d + r where q is the quotient and r the remainder. Then the mixed fraction is q r/d.
Let f be a function with domain D in R, the real numbers, and D is an open set in R. Then the derivative of f at the point c is defined as: f'(c) =lim as x-> c of the difference quotient [f(x)-f(c)]/[x-c] If that limit exits, the function is called differentiable at c. If f is differentiable at every point in D then f is called differentiable in D.
They are called A, B, C, D, E.They are called A, B, C, D, E.They are called A, B, C, D, E.They are called A, B, C, D, E.
When A/B is divided by C/D, just flip C/D into D/C and multiply. Outcome should be AD/BC.
No. is it not a, b,c, or d.